If the focus of the parabola x 2-ky+3 0
WebQuestion: An equation of a parabola is given. (x-3)^(2)=4(y+2) (a) ... An equation of a parabola is given. (x-3)^(2)=4(y+2) (a) Find the vertex, focus, and directrix of the par. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the ... WebCorrect option is A) focusofparabola x 2−ky+3=0is(0,2),thenvalueofk byputtingx=0andy=2ineq n⇒0−k×2+3=0 ⇒−2k+3=0 2k=3,k= 23 Was this answer helpful? …
If the focus of the parabola x 2-ky+3 0
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Web6 okt. 2024 · Key Concepts. A parabola is the set of all points (x,y) in a plane that are the same distance from a fixed line, called the directrix, and a fixed point (the focus) not on … WebIa. Find a Mibius transformation that sends the triple (1,2,3) to (1,i,-1) . Call it M. I. Find Mahius (rausformation tat sends thie triple (1,linfty,3) to (1,i,l...
WebWe begin with the former. Figure 4. Let ( x, y) be a point on the parabola with vertex ( 0, 0), focus ( 0, p), and directrix y = − p as shown in Figure 4. The distance d from point ( x, y) … WebIf the focus of the parabola `x^2-k y+3=0` is (0,2), then a values of `k` is (are) 4 (b) 6 (c) 3 (d) 2 A. 4 B. 6 C. 3 D. 2 LIVE Course for free Rated by 1 million+ students
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WebSolution The correct option is D 2 Given parabola is x2−ky+3 =0 or x2 =k(y− 3 k) Le x =X,y− 3 k=Y then the parabola is X2 = kY whose focus is (0, k 4). Therefore, the focus of x2 …
WebIf you have the equation of a parabola in vertex form y = a (x − h) 2 + k, then the vertex is at (h, k) and the focus is (h, k + 1 4 a). Notice that here we are working with a parabola with a vertical axis of symmetry, so the x … do work nationWebIdentify the vertex, focus, axis 2x^(2)+24x+y+75=0. Expert Answer. Who are the experts? ... 2 x 2 + 24 x + y + 75 = 0 We have to find the vertex, focus and axis of the given parabola. View the full answer. Step 2/5. Step 3/5. Step 4/5. Step 5/5. Final answer. Previous question Next question. This problem has been solved! cleaning ivory with toothpasteWebEquation of the circle is [x^2+y^2+4x+6y-12=0] [x^2+4x+4+y^2+6y+9=12+4+9] [(x+2)^2+(y+3)^2=(5)^2] (i)Thus centre of the circle = (-2,-3) radius of the circle= … cleaning ivoryWeb17 jul. 2024 · The equation of directrix is x + y = 3 and focus is (- 2,1). We know that, The directrix and axis are perpendicular to each other. The axis also passes through the … cleaning ivory keysWebGiven the focus of the parabola is (0, 3) and directrix y = -3. It is clear that the parabola is open upwards. When focus is (0, a) and directrix is y = -a then the standard formula is. x … do work pay for eye testsWebUse the standard form identified in Step 1 to determine the vertex, axis of symmetry, focus, equation of the directrix, and endpoints of the focal diameter. If the equation is in the … do working families tax creditWeba^2 + b^2 = c^2. We can use this equation to represent the distance from a random point on the parabola (x, y) to the focus and directrix. Let's say that the focus of this parabola is … do workout machines work