WebIf the sum of the first 6 terms of an A.P. is 36 and that of the first 16 terms is 256, find the sum of the first 10 terms. Answer: From the question, it is given that, \begin{array}{l} S_{6}=36 \\ S_{16}=256 \end{array} We know that, \begin{array}{l} S_{n}=(n / 2)(2 a+(n-1) d) \\ S_{6}=(6 / 2)(2 a+(6-1) d)=36 \end{array} 3 (2a + 5d) = 36 ... WebQuestion 6 : If S = {square, rectangle, circle, rhombus, triangle}, list the elements of the following subset of S. (i) The set of shapes which have 4 equal sides. (ii) The set of shapes which have no sides. (iii) The set of shapes in which the sum of all interior angles is 180o. (iv) The set of shapes which have 5 sides.

[Solved] If n[P(A)] = 256, find n(A) - Brainly.in

WebYou need log2(n) bits to address n bytes. For example, you can store 256 different values in an 8 bit number, so 8 bits can address 256 bytes. 2 10 = 1024, so you need 10 bits to address every byte in a kilobyte. Likewise, you need 20 bits to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte. 2 32 = 4294967296, which is … Web27 apr. 2024 · Respuesta: 23. Explicación paso a paso: n[P(A)] = 2 elevado a la n(A) ⇒ n[P(A)] = 256 = 2⁸ ⇒ n(A) = 8. ⇒ n[P(B)] = 32 = 2⁵ ⇒ n(B) = 5 cheap sissy squat machine

mysql - How long is the SHA256 hash? - Stack Overflow

Web2 mrt. 2024 · A sha256 is 256 bits long -- as its name indicates. Since sha256 returns a hexadecimal representation, 4 bits are enough to encode each character (instead of 8, like for ASCII), so 256 bits would represent 64 hex characters, therefore you need a varchar (64), or even a char (64), as the length is always the same, not varying at all. WebThe number of proper subsets = n[P(W)] – 1 = 2 3 – 1 = 8 – 1 = 7 (ii) Given X ={1,2,3, } X 2 = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100} n(X) = 10 The Number of subsets = n[P(X)] = 2 10 = 1024 The Number of proper subsets = n[P(X)] – 1 = 2 10 – 1 = 1024 – 1 = 1023. 10th Maths Exercise 1.2 Samacheer Kalvi Question 10. (i) If n(A) = 4 ... Web27 mei 2015 · Traditionally, the "length" of a RSA key is the length, in bits, of the modulus. When a RSA key is said to have length "2048", it really means that the modulus value lies between 2 2047 and 2 2048. Since the public and private key of a given pair share the same modulus, they also have, by definition, the same "length". cheap sisal rugs 8x10